Wednesday 13 June 2012

How to format datetime & date in Sql Server 2005

Execute the following Microsoft SQL Server T-SQL datetime and date formatting scripts in Management Studio Query Editor to demonstrate the multitude of temporal data formats available in SQL Server.

First we start with the conversion options available for sql datetime formats with century (YYYY or CCYY format). Subtracting 100 from the Style (format) number will transform dates without century (YY). For example Style 103 is with century, Style 3 is without century. The default Style values – Style 0 or 100, 9 or 109, 13 or 113, 20 or 120, and 21 or 121 – always return the century (yyyy) format.

 

– Microsoft SQL Server T-SQL date and datetime formats

– Date time formats – mssql datetime

– MSSQL getdate returns current system date and time in standard internal format

SELECT convert(varchar, getdate(), 100) – mon dd yyyy hh:mmAM (or PM)

– Oct  2 2008 11:01AM

SELECT convert(varchar, getdate(), 101) – mm/dd/yyyy - 10/02/2008

SELECT convert(varchar, getdate(), 102) – yyyy.mm.dd – 2008.10.02

SELECT convert(varchar, getdate(), 103) – dd/mm/yyyy

SELECT convert(varchar, getdate(), 104) – dd.mm.yyyy

SELECT convert(varchar, getdate(), 105) – dd-mm-yyyy

SELECT convert(varchar, getdate(), 106) – dd mon yyyy

SELECT convert(varchar, getdate(), 107) – mon dd, yyyy

SELECT convert(varchar, getdate(), 108) – hh:mm:ss

SELECT convert(varchar, getdate(), 109) – mon dd yyyy hh:mm:ss:mmmAM (or PM)

– Oct  2 2008 11:02:44:013AM

SELECT convert(varchar, getdate(), 110) – mm-dd-yyyy

SELECT convert(varchar, getdate(), 111) – yyyy/mm/dd

SELECT convert(varchar, getdate(), 112) – yyyymmdd

SELECT convert(varchar, getdate(), 113) – dd mon yyyy hh:mm:ss:mmm

– 02 Oct 2008 11:02:07:577

SELECT convert(varchar, getdate(), 114) – hh:mm:ss:mmm(24h)

SELECT convert(varchar, getdate(), 120) – yyyy-mm-dd hh:mm:ss(24h)

SELECT convert(varchar, getdate(), 121) – yyyy-mm-dd hh:mm:ss.mmm

SELECT convert(varchar, getdate(), 126) – yyyy-mm-ddThh:mm:ss.mmm

– 2008-10-02T10:52:47.513

– SQL create different date styles with t-sql string functions

SELECT replace(convert(varchar, getdate(), 111), ‘/’, ‘ ‘) – yyyy mm dd

SELECT convert(varchar(7), getdate(), 126)                 – yyyy-mm

SELECT right(convert(varchar, getdate(), 106), 8)          – mon yyyy

————

– SQL Server date formatting function – convert datetime to string

————

– SQL datetime functions

– SQL Server date formats

– T-SQL convert dates

– Formatting dates sql server

CREATE FUNCTION dbo.fnFormatDate (@Datetime DATETIME, @FormatMask VARCHAR(32))

RETURNS VARCHAR(32)

AS

BEGIN

DECLARE @StringDate VARCHAR(32)

SET @StringDate = @FormatMask

IF (CHARINDEX (‘YYYY’,@StringDate) > 0)

SET @StringDate = REPLACE(@StringDate, ‘YYYY’,

DATENAME(YY, @Datetime))

IF (CHARINDEX (‘YY’,@StringDate) > 0)

SET @StringDate = REPLACE(@StringDate, ‘YY’,

RIGHT(DATENAME(YY, @Datetime),2))

IF (CHARINDEX (‘Month’,@StringDate) > 0)

SET @StringDate = REPLACE(@StringDate, ‘Month’,

DATENAME(MM, @Datetime))

IF (CHARINDEX (‘MON’,@StringDate COLLATE SQL_Latin1_General_CP1_CS_AS)>0)

SET @StringDate = REPLACE(@StringDate, ‘MON’,

LEFT(UPPER(DATENAME(MM, @Datetime)),3))

IF (CHARINDEX (‘Mon’,@StringDate) > 0)

SET @StringDate = REPLACE(@StringDate, ‘Mon’,

LEFT(DATENAME(MM, @Datetime),3))

IF (CHARINDEX (‘MM’,@StringDate) > 0)

SET @StringDate = REPLACE(@StringDate, ‘MM’,

RIGHT(’0′+CONVERT(VARCHAR,DATEPART(MM, @Datetime)),2))

IF (CHARINDEX (‘M’,@StringDate) > 0)

SET @StringDate = REPLACE(@StringDate, ‘M’,

CONVERT(VARCHAR,DATEPART(MM, @Datetime)))

IF (CHARINDEX (‘DD’,@StringDate) > 0)

SET @StringDate = REPLACE(@StringDate, ‘DD’,

RIGHT(’0′+DATENAME(DD, @Datetime),2))

IF (CHARINDEX (‘D’,@StringDate) > 0)

SET @StringDate = REPLACE(@StringDate, ‘D’,

DATENAME(DD, @Datetime))

RETURN @StringDate

END

GO

 

– Microsoft SQL Server date format function test

– MSSQL formatting dates

SELECT dbo.fnFormatDate (getdate(), ‘MM/DD/YYYY’)           – 01/03/2012

SELECT dbo.fnFormatDate (getdate(), ‘DD/MM/YYYY’)           – 03/01/2012

SELECT dbo.fnFormatDate (getdate(), ‘M/DD/YYYY’)            – 1/03/2012

SELECT dbo.fnFormatDate (getdate(), ‘M/D/YYYY’)             – 1/3/2012

SELECT dbo.fnFormatDate (getdate(), ‘M/D/YY’)               – 1/3/12

SELECT dbo.fnFormatDate (getdate(), ‘MM/DD/YY’)             – 01/03/12

SELECT dbo.fnFormatDate (getdate(), ‘MON DD, YYYY’)         – JAN 03, 2012

SELECT dbo.fnFormatDate (getdate(), ‘Mon DD, YYYY’)         – Jan 03, 2012

SELECT dbo.fnFormatDate (getdate(), ‘Month DD, YYYY’)       – January 03, 2012

SELECT dbo.fnFormatDate (getdate(), ‘YYYY/MM/DD’)           – 2012/01/03

SELECT dbo.fnFormatDate (getdate(), ‘YYYYMMDD’)             – 20120103

SELECT dbo.fnFormatDate (getdate(), ‘YYYY-MM-DD’)           – 2012-01-03

– CURRENT_TIMESTAMP returns current system date and time in standard internal format

SELECT dbo.fnFormatDate (CURRENT_TIMESTAMP,‘YY.MM.DD’)      – 12.01.03

GO

————

 

/***** SELECTED SQL DATE/DATETIME FORMATS WITH NAMES *****/

 

– SQL format datetime

– Default format: Oct 23 2006 10:40AM

SELECT [Default]=CONVERT(varchar,GETDATE(),100)

 

– US-Style format: 10/23/2006

SELECT [US-Style]=CONVERT(char,GETDATE(),101)

 

– ANSI format: 2006.10.23

SELECT [ANSI]=CONVERT(char,CURRENT_TIMESTAMP,102)

 

– UK-Style format: 23/10/2006

SELECT [UK-Style]=CONVERT(char,GETDATE(),103)

 

– German format: 23.10.2006

SELECT [German]=CONVERT(varchar,GETDATE(),104)

 

– ISO format: 20061023

SELECT ISO=CONVERT(varchar,GETDATE(),112)

 

– ISO8601 format: 2008-10-23T19:20:16.003

SELECT [ISO8601]=CONVERT(varchar,GETDATE(),126)

————

 

– SQL Server datetime formats

– Century date format MM/DD/YYYY usage in a query

– Format dates SQL Server 2005

SELECT TOP (1)

SalesOrderID,

OrderDate = CONVERT(char(10), OrderDate, 101),

OrderDateTime = OrderDate

FROM AdventureWorks.Sales.SalesOrderHeader

/* Result

 

SalesOrderID      OrderDate               OrderDateTime

43697             07/01/2001          2001-07-01 00:00:00.000

*/

 

– SQL update datetime column

– SQL datetime DATEADD

UPDATE Production.Product

SET ModifiedDate=DATEADD(dd,1, ModifiedDate)

WHERE ProductID = 1001

 

– MM/DD/YY date format

– Datetime format sql

SELECT TOP (1)

SalesOrderID,

OrderDate = CONVERT(varchar(8), OrderDate, 1),

OrderDateTime = OrderDate

FROM AdventureWorks.Sales.SalesOrderHeader

ORDER BY SalesOrderID desc

/* Result

 

SalesOrderID      OrderDate         OrderDateTime

75123             07/31/04          2004-07-31 00:00:00.000

*/

 

– Combining different style formats for date & time

– Datetime formats

– Datetime formats sql

DECLARE @Date DATETIME

SET @Date = ’2015-12-22 03:51 PM’

SELECT CONVERT(CHAR(10),@Date,110) + SUBSTRING(CONVERT(varchar,@Date,0),12,8)

– Result: 12-22-2015  3:51PM

 

– Microsoft SQL Server cast datetime to string

SELECT stringDateTime=CAST (getdate() as varchar)

– Result: Dec 29 2012  3:47AM

————

– SQL Server date and time functions overview

————

– SQL Server CURRENT_TIMESTAMP function

– SQL Server datetime functions

– local NYC – EST – Eastern Standard Time zone

– SQL DATEADD function – SQL DATEDIFF function

SELECT CURRENT_TIMESTAMP                        – 2012-01-05 07:02:10.577

– SQL Server DATEADD function

SELECT DATEADD(month,2,’2012-12-09′)            – 2013-02-09 00:00:00.000

– SQL Server DATEDIFF function

SELECT DATEDIFF(day,’2012-12-09′,’2013-02-09′)  – 62

– SQL Server DATENAME function

SELECT DATENAME(month,   ’2012-12-09′)          – December

SELECT DATENAME(weekday, ’2012-12-09′)          – Sunday

– SQL Server DATEPART function

SELECT DATEPART(month, ’2012-12-09′)            – 12

– SQL Server DAY function

SELECT DAY(’2012-12-09′)                        – 9

– SQL Server GETDATE function

– local NYC – EST – Eastern Standard Time zone

SELECT GETDATE()                                – 2012-01-05 07:02:10.577

– SQL Server GETUTCDATE function

– London – Greenwich Mean Time

SELECT GETUTCDATE()                             – 2012-01-05 12:02:10.577

– SQL Server MONTH function

SELECT MONTH(’2012-12-09′)                      – 12

– SQL Server YEAR function

SELECT YEAR(’2012-12-09′)                       – 2012

 

 

————

– T-SQL Date and time function application

– CURRENT_TIMESTAMP and getdate() are the same in T-SQL

————

– SQL first day of the month

– SQL first date of the month

– SQL first day of current month – 2012-01-01 00:00:00.000

SELECT DATEADD(dd,0,DATEADD(mm, DATEDIFF(mm,0,CURRENT_TIMESTAMP),0))

– SQL last day of the month

– SQL last date of the month

– SQL last day of current month – 2012-01-31 00:00:00.000

SELECT DATEADD(dd,-1,DATEADD(mm, DATEDIFF(mm,0,CURRENT_TIMESTAMP)+1,0))

– SQL first day of last month

– SQL first day of previous month – 2011-12-01 00:00:00.000

SELECT DATEADD(mm,-1,DATEADD(mm, DATEDIFF(mm,0,CURRENT_TIMESTAMP),0))

– SQL last day of last month

– SQL last day of previous month – 2011-12-31 00:00:00.000

SELECT DATEADD(dd,-1,DATEADD(mm, DATEDIFF(mm,0,DATEADD(MM,-1,GETDATE()))+1,0))

– SQL first day of next month – 2012-02-01 00:00:00.000

SELECT DATEADD(mm,1,DATEADD(mm, DATEDIFF(mm,0,CURRENT_TIMESTAMP),0))

– SQL last day of next month – 2012-02-28 00:00:00.000

SELECT DATEADD(dd,-1,DATEADD(mm, DATEDIFF(mm,0,DATEADD(MM,1,GETDATE()))+1,0))

GO

– SQL first day of a month – 2012-10-01 00:00:00.000

DECLARE @Date datetime; SET @Date = ’2012-10-23′

SELECT DATEADD(dd,0,DATEADD(mm, DATEDIFF(mm,0,@Date),0))

GO

– SQL last day of a month – 2012-03-31 00:00:00.000

DECLARE @Date datetime; SET @Date = ’2012-03-15′

SELECT DATEADD(dd,-1,DATEADD(mm, DATEDIFF(mm,0,@Date)+1,0))

GO

– SQL first day of year

– SQL first day of the year  -  2012-01-01 00:00:00.000

SELECT DATEADD(yy, DATEDIFF(yy,0,CURRENT_TIMESTAMP), 0)

– SQL last day of year

– SQL last day of the year   – 2012-12-31 00:00:00.000

SELECT DATEADD(yy,1, DATEADD(dd, -1, DATEADD(yy,

DATEDIFF(yy,0,CURRENT_TIMESTAMP), 0)))

– SQL last day of last year

– SQL last day of previous year   – 2011-12-31 00:00:00.000

SELECT DATEADD(dd,-1,DATEADD(yy,DATEDIFF(yy,0,CURRENT_TIMESTAMP), 0))

GO

– SQL calculate age in years, months, days

– SQL table-valued function

– SQL user-defined function – UDF

– SQL Server age calculation – date difference

– Format dates SQL Server 2008

USE AdventureWorks2008;

GO

CREATE FUNCTION fnAge  (@BirthDate DATETIME)

RETURNS @Age TABLE(Years  INT,

Months INT,

Days   INT)

AS

BEGIN

DECLARE  @EndDate     DATETIME, @Anniversary DATETIME

SET @EndDate = Getdate()

SET @Anniversary = Dateadd(yy,Datediff(yy,@BirthDate,@EndDate),@BirthDate)

INSERT @Age

SELECT Datediff(yy,@BirthDate,@EndDate) - (CASE

WHEN @Anniversary > @EndDate THEN 1

ELSE 0

END), 0, 0

UPDATE @Age     SET    Months = Month(@EndDate - @Anniversary) - 1

UPDATE @Age     SET    Days = Day(@EndDate - @Anniversary) - 1

RETURN

END

GO

 

– Test table-valued UDF

SELECT * FROM   fnAge(’1956-10-23′)

SELECT * FROM   dbo.fnAge(’1956-10-23′)

/* Results

Years       Months      Days

52          4           1

*/

 

———-

– SQL date range between

———-

– SQL between dates

USE AdventureWorks;

– SQL between

SELECT POs=COUNT(*) FROM Purchasing.PurchaseOrderHeader

WHERE OrderDate BETWEEN ’20040301′ AND ’20040315′

– Result: 108

 

– BETWEEN operator is equivalent to >=…AND….<=

SELECT POs=COUNT(*) FROM Purchasing.PurchaseOrderHeader

WHERE OrderDate

BETWEEN ’2004-03-01 00:00:00.000′ AND ’2004-03-15  00:00:00.000′

/*

Orders with OrderDates

’2004-03-15  00:00:01.000′  – 1 second after midnight (12:00AM)

’2004-03-15  00:01:00.000′  – 1 minute after midnight

’2004-03-15  01:00:00.000′  – 1 hour after midnight

 

are not included in the two queries above.

*/

– To include the entire day of 2004-03-15 use the following two solutions

SELECT POs=COUNT(*) FROM Purchasing.PurchaseOrderHeader

WHERE OrderDate >= ’20040301′ AND OrderDate < ’20040316′

 

– SQL between with DATE type (SQL Server 2008)

SELECT POs=COUNT(*) FROM Purchasing.PurchaseOrderHeader

WHERE CONVERT(DATE, OrderDate) BETWEEN ’20040301′ AND ’20040315′

———-

– Non-standard format conversion: 2011 December 14

– SQL datetime to string

SELECT [YYYY Month DD] =

CAST(YEAR(GETDATE()) AS VARCHAR(4))+ ‘ ‘+

DATENAME(MM, GETDATE()) + ‘ ‘ +

CAST(DAY(GETDATE()) AS VARCHAR(2))

 

– Converting datetime to YYYYMMDDHHMMSS format: 20121214172638

SELECT replace(convert(varchar, getdate(),111),‘/’,”) +

replace(convert(varchar, getdate(),108),‘:’,”)

 

– Datetime custom format conversion to YYYY_MM_DD

select CurrentDate=rtrim(year(getdate())) + ‘_’ +

right(’0′ + rtrim(month(getdate())),2) + ‘_’ +

right(’0′ + rtrim(day(getdate())),2)

 

– Converting seconds to HH:MM:SS format

declare @Seconds int

set @Seconds = 10000

select TimeSpan=right(’0′ +rtrim(@Seconds / 3600),2) + ‘:’ +

right(’0′ + rtrim((@Seconds % 3600) / 60),2) + ‘:’ +

right(’0′ + rtrim(@Seconds % 60),2)

– Result: 02:46:40

 

– Test result

select 2*3600 + 46*60 + 40

– Result: 10000

– Set the time portion of a datetime value to 00:00:00.000

– SQL strip time from date

– SQL strip time from datetime

SELECT CURRENT_TIMESTAMP ,DATEADD(dd, DATEDIFF(dd, 0, CURRENT_TIMESTAMP), 0)

– Results: 2014-01-23 05:35:52.793 2014-01-23 00:00:00.000

/*******

 

VALID DATE RANGES FOR DATE/DATETIME DATA TYPES

 

SMALLDATETIME date range:

January 1, 1900 through June 6, 2079

 

DATETIME date range:

January 1, 1753 through December 31, 9999

 

DATETIME2 date range (SQL Server 2008):

January 1,1 AD through December 31, 9999 AD

 

DATE date range (SQL Server 2008):

January 1, 1 AD through December 31, 9999 AD

 

*******/

– Selecting with CONVERT into different styles

– Note: Only Japan & ISO styles can be used in ORDER BY

SELECT TOP(1)

Italy  = CONVERT(varchar, OrderDate, 105)

, USA    = CONVERT(varchar, OrderDate, 110)

, Japan  = CONVERT(varchar, OrderDate, 111)

, ISO    = CONVERT(varchar, OrderDate, 112)

FROM AdventureWorks.Purchasing.PurchaseOrderHeader

ORDER BY PurchaseOrderID DESC

/* Results

Italy       USA         Japan       ISO

25-07-2004  07-25-2004  2004/07/25  20040725

*/

– SQL Server convert date to integer

DECLARE @Datetime datetime

SET @Datetime = ’2012-10-23 10:21:05.345′

SELECT DateAsInteger = CAST (CONVERT(varchar,@Datetime,112) as INT)

– Result: 20121023

 

– SQL Server convert integer to datetime

DECLARE @intDate int

SET @intDate = 20120315

SELECT IntegerToDatetime = CAST(CAST(@intDate as varchar) as datetime)

– Result: 2012-03-15 00:00:00.000

————

– SQL Server CONVERT script applying table INSERT/UPDATE

————

– SQL Server convert date

– Datetime column is converted into date only string column

USE tempdb;

GO

CREATE TABLE sqlConvertDateTime   (

DatetimeCol datetime,

DateCol char(8));

INSERT sqlConvertDateTime (DatetimeCol) SELECT GETDATE()

 

UPDATE sqlConvertDateTime

SET DateCol = CONVERT(char(10), DatetimeCol, 112)

SELECT * FROM sqlConvertDateTime

 

– SQL Server convert datetime

– The string date column is converted into datetime column

UPDATE sqlConvertDateTime

SET DatetimeCol = CONVERT(Datetime, DateCol, 112)

SELECT * FROM sqlConvertDateTime

 

– Adding a day to the converted datetime column with DATEADD

UPDATE sqlConvertDateTime

SET DatetimeCol = DATEADD(day, 1, CONVERT(Datetime, DateCol, 112))

SELECT * FROM sqlConvertDateTime

 

– Equivalent formulation

– SQL Server cast datetime

UPDATE sqlConvertDateTime

SET DatetimeCol = DATEADD(dd, 1, CAST(DateCol AS datetime))

SELECT * FROM sqlConvertDateTime

GO

DROP TABLE sqlConvertDateTime

GO

/* First results

DatetimeCol                   DateCol

2014-12-25 16:04:15.373       20141225 */

 

/* Second results:

DatetimeCol                   DateCol

2014-12-25 00:00:00.000       20141225  */

 

/* Third results:

DatetimeCol                   DateCol

2014-12-26 00:00:00.000       20141225  */

————

– SQL month sequence – SQL date sequence generation with table variable

– SQL Server cast string to datetime – SQL Server cast datetime to string

– SQL Server insert default values method

DECLARE @Sequence table (Sequence int identity(1,1))

DECLARE @i int; SET @i = 0

DECLARE @StartDate datetime;

SET @StartDate = CAST(CONVERT(varchar, year(getdate()))+

RIGHT(’0′+convert(varchar,month(getdate())),2) + ’01′ AS DATETIME)

WHILE ( @i < 120)

BEGIN

INSERT @Sequence DEFAULT VALUES

SET @i = @i + 1

END

SELECT MonthSequence = CAST(DATEADD(month, Sequence,@StartDate) AS varchar)

FROM @Sequence

GO

/* Partial results:

MonthSequence

Jan  1 2012 12:00AM

Feb  1 2012 12:00AM

Mar  1 2012 12:00AM

Apr  1 2012 12:00AM

*/

————

 

————

– SQL Server Server datetime internal storage

– SQL Server datetime formats

————

– SQL Server datetime to hex

SELECT Now=CURRENT_TIMESTAMP, HexNow=CAST(CURRENT_TIMESTAMP AS BINARY(8))

/* Results

 

Now                     HexNow

2009-01-02 17:35:59.297 0x00009B850122092D

*/

– SQL Server date part – left 4 bytes – Days since 1900-01-01

SELECT Now=DATEADD(DAY, CONVERT(INT, 0x00009B85), ’19000101′)

GO

– Result: 2009-01-02 00:00:00.000

 

– SQL time part – right 4 bytes – milliseconds since midnight

– 1000/300 is an adjustment factor

– SQL dateadd to Midnight

SELECT Now=DATEADD(MS, (1000.0/300)* CONVERT(BIGINT, 0x0122092D), ’2009-01-02′)

GO

– Result: 2009-01-02 17:35:59.290

————

————

– String date and datetime date&time columns usage

– SQL Server datetime formats in tables

————

USE tempdb;

SET NOCOUNT ON;

– SQL Server select into table create

SELECT TOP (5)

FullName=convert(nvarchar(50),FirstName+‘ ‘+LastName),

BirthDate = CONVERT(char(8), BirthDate,112),

ModifiedDate = getdate()

INTO Employee

FROM AdventureWorks.HumanResources.Employee e

INNER JOIN AdventureWorks.Person.Contact c

ON c.ContactID = e.ContactID

ORDER BY EmployeeID

GO

– SQL Server alter table

ALTER TABLE Employee ALTER COLUMN FullName nvarchar(50) NOT NULL

GO

ALTER TABLE Employee

ADD CONSTRAINT [PK_Employee] PRIMARY KEY (FullName )

GO

/* Results

 

Table definition for the Employee table

Note: BirthDate is string date (only)

 

CREATE TABLE dbo.Employee(

FullName nvarchar(50) NOT NULL PRIMARY KEY,

BirthDate char(8) NULL,

ModifiedDate datetime NOT NULL

)

*/

SELECT * FROM Employee ORDER BY FullName

GO

/* Results

FullName                BirthDate   ModifiedDate

Guy Gilbert             19720515    2009-01-03 10:10:19.217

Kevin Brown             19770603    2009-01-03 10:10:19.217

Rob Walters             19650123    2009-01-03 10:10:19.217

Roberto Tamburello      19641213    2009-01-03 10:10:19.217

Thierry D’Hers          19490829    2009-01-03 10:10:19.217

*/

 

– SQL Server age

SELECT FullName, Age = DATEDIFF(YEAR, BirthDate, GETDATE()),

RowMaintenanceDate = CAST (ModifiedDate AS varchar)

FROM Employee ORDER BY FullName

GO

/* Results

FullName                Age   RowMaintenanceDate

Guy Gilbert             37    Jan  3 2009 10:10AM

Kevin Brown             32    Jan  3 2009 10:10AM

Rob Walters             44    Jan  3 2009 10:10AM

Roberto Tamburello      45    Jan  3 2009 10:10AM

Thierry D’Hers          60    Jan  3 2009 10:10AM

*/

 

– SQL Server age of Rob Walters on specific dates

– SQL Server string to datetime implicit conversion with DATEADD

SELECT AGE50DATE = DATEADD(YY, 50, ’19650123′)

GO

– Result: 2015-01-23 00:00:00.000

 

– SQL Server datetime to string, Italian format for ModifiedDate

– SQL Server string to datetime implicit conversion with DATEDIFF

SELECT FullName,

AgeDEC31 = DATEDIFF(YEAR, BirthDate, ’20141231′),

AgeJAN01 = DATEDIFF(YEAR, BirthDate, ’20150101′),

AgeJAN23 = DATEDIFF(YEAR, BirthDate, ’20150123′),

AgeJAN24 = DATEDIFF(YEAR, BirthDate, ’20150124′),

ModDate = CONVERT(varchar, ModifiedDate, 105)

FROM Employee

WHERE FullName = ‘Rob Walters’

ORDER BY FullName

GO

/* Results

Important Note: age increments on Jan 1 (not as commonly calculated)

 

FullName    AgeDEC31    AgeJAN01    AgeJAN23    AgeJAN24    ModDate

Rob Walters 49          50          50          50          03-01-2009

*/

 

————

– SQL combine integer date & time into datetime

————

– Datetime format sql

– SQL stuff

DECLARE @DateTimeAsINT TABLE ( ID int identity(1,1) primary key,

DateAsINT int,

TimeAsINT int

)

– NOTE: leading zeroes in time is for readability only!

INSERT @DateTimeAsINT (DateAsINT, TimeAsINT) VALUES (20121023, 235959)

INSERT @DateTimeAsINT (DateAsINT, TimeAsINT) VALUES (20121023, 010204)

INSERT @DateTimeAsINT (DateAsINT, TimeAsINT) VALUES (20121023, 002350)

INSERT @DateTimeAsINT (DateAsINT, TimeAsINT) VALUES (20121023, 000244)

INSERT @DateTimeAsINT (DateAsINT, TimeAsINT) VALUES (20121023, 000050)

INSERT @DateTimeAsINT (DateAsINT, TimeAsINT) VALUES (20121023, 000006)

 

SELECT DateAsINT, TimeAsINT,

CONVERT(datetime, CONVERT(varchar(8), DateAsINT) + ‘ ‘+

STUFF(STUFF ( RIGHT(REPLICATE(’0′, 6) + CONVERT(varchar(6), TimeAsINT), 6),

3, 0, ‘:’), 6, 0, ‘:’))  AS DateTimeValue

FROM   @DateTimeAsINT

ORDER BY ID

GO

/* Results

DateAsINT   TimeAsINT   DateTimeValue

20121023    235959      2012-10-23 23:59:59.000

20121023    10204       2012-10-23 01:02:04.000

20121023    2350        2012-10-23 00:23:50.000

20121023    244         2012-10-23 00:02:44.000

20121023    50          2012-10-23 00:00:50.000

20121023    6           2012-10-23 00:00:06.000

*/

————

 

– SQL Server string to datetime, implicit conversion with assignment

UPDATE Employee SET ModifiedDate = ’20150123′

WHERE FullName = ‘Rob Walters’

GO

SELECT ModifiedDate FROM Employee WHERE FullName = ‘Rob Walters’

GO

– Result: 2015-01-23 00:00:00.000

 

/* SQL string date, assemble string date from datetime parts  */

– SQL Server cast string to datetime – sql convert string date

– SQL Server number to varchar conversion

– SQL Server leading zeroes for month and day

– SQL Server right string function

UPDATE Employee SET BirthDate =

CONVERT(char(4),YEAR(CAST(’1965-01-23′ as DATETIME)))+

RIGHT(’0′+CONVERT(varchar,MONTH(CAST(’1965-01-23′ as DATETIME))),2)+

RIGHT(’0′+CONVERT(varchar,DAY(CAST(’1965-01-23′ as DATETIME))),2)

WHERE FullName = ‘Rob Walters’

GO

SELECT BirthDate FROM Employee WHERE FullName = ‘Rob Walters’

GO

– Result: 19650123

 

– Perform cleanup action

DROP TABLE Employee

– SQL nocount

SET NOCOUNT OFF;

GO

————

————

– sql isdate function

————

USE tempdb;

– sql newid – random sort

SELECT top(3) SalesOrderID,

stringOrderDate = CAST (OrderDate AS varchar)

INTO DateValidation

FROM AdventureWorks.Sales.SalesOrderHeader

ORDER BY NEWID()

GO

SELECT * FROM DateValidation

/* Results

SalesOrderID      stringOrderDate

56720             Oct 26 2003 12:00AM

73737             Jun 25 2004 12:00AM

70573             May 14 2004 12:00AM

*/

– SQL update with top

UPDATE TOP(1) DateValidation

SET stringOrderDate = ‘Apb 29 2004 12:00AM’

GO

– SQL string to datetime fails without validation

SELECT SalesOrderID, OrderDate = CAST (stringOrderDate as datetime)

FROM DateValidation

GO

/* Msg 242, Level 16, State 3, Line 1

The conversion of a varchar data type to a datetime data type resulted in an

out-of-range value.

*/

– sql isdate – filter for valid dates

SELECT SalesOrderID, OrderDate = CAST (stringOrderDate as datetime)

FROM DateValidation

WHERE ISDATE(stringOrderDate) = 1

GO

/* Results

SalesOrderID      OrderDate

73737             2004-06-25 00:00:00.000

70573             2004-05-14 00:00:00.000

*/

– SQL drop table

DROP TABLE DateValidation

Go

 

————

– SELECT between two specified dates – assumption TIME part is 00:00:00.000

————

– SQL datetime between

– SQL select between two dates

SELECT EmployeeID, RateChangeDate

FROM AdventureWorks.HumanResources.EmployeePayHistory

WHERE RateChangeDate >= ’1997-11-01′ AND

RateChangeDate < DATEADD(dd,1,’1998-01-05′)

GO

/* Results

EmployeeID  RateChangeDate

3           1997-12-12 00:00:00.000

4           1998-01-05 00:00:00.000

*/

 

/* Equivalent to

 

– SQL datetime range

SELECT EmployeeID, RateChangeDate

FROM AdventureWorks.HumanResources.EmployeePayHistory

WHERE RateChangeDate >= ’1997-11-01 00:00:00′ AND

RateChangeDate <  ’1998-01-06 00:00:00′

GO

*/

————

– SQL datetime language setting

– SQL Nondeterministic function usage – result varies with language settings

SET LANGUAGE  ‘us_english’;  –– Jan 12 2015 12:00AM

SELECT US = convert(VARCHAR,convert(DATETIME,’01/12/2015′));

SET LANGUAGE  ‘British’;     –– Dec  1 2015 12:00AM

SELECT UK = convert(VARCHAR,convert(DATETIME,’01/12/2015′));

SET LANGUAGE  ‘German’;      –– Dez  1 2015 12:00AM

SET LANGUAGE  ‘Deutsch’;     –– Dez  1 2015 12:00AM

SELECT Germany = convert(VARCHAR,convert(DATETIME,’01/12/2015′));

SET LANGUAGE  ‘French’;      –– déc  1 2015 12:00AM

SELECT France = convert(VARCHAR,convert(DATETIME,’01/12/2015′));

SET LANGUAGE  ‘Spanish’;     –– Dic  1 2015 12:00AM

SELECT Spain = convert(VARCHAR,convert(DATETIME,’01/12/2015′));

SET LANGUAGE  ‘Hungarian’;   –– jan 12 2015 12:00AM

SELECT Hungary = convert(VARCHAR,convert(DATETIME,’01/12/2015′));

SET LANGUAGE  ‘us_english’;

GO

————

————

– Function for Monday dates calculation

————

USE AdventureWorks2008;

GO

– SQL user-defined function

– SQL scalar function – UDF

CREATE FUNCTION fnMondayDate

(@Year          INT,

@Month         INT,

@MondayOrdinal INT)

RETURNS DATETIME

AS

BEGIN

DECLARE  @FirstDayOfMonth CHAR(10),

@SeedDate        CHAR(10)

SET @FirstDayOfMonth = convert(VARCHAR,@Year) + ‘-’ + convert(VARCHAR,@Month) + ‘-01′

SET @SeedDate = ’1900-01-01′

RETURN DATEADD(DD,DATEDIFF(DD,@SeedDate,DATEADD(DD,(@MondayOrdinal * 7) - 1,

@FirstDayOfMonth)) / 7 * 7,  @SeedDate)

END

GO

 

– Test Datetime UDF

– Third Monday in Feb, 2015

SELECT dbo.fnMondayDate(2016,2,3)

– 2015-02-16 00:00:00.000

 

– First Monday of current month

SELECT dbo.fnMondayDate(Year(getdate()),Month(getdate()),1)

– 2009-02-02 00:00:00.000

————

Remove duplicate rows from a DataTable

--------- Demo Removing Duplicate rows in a DataTable ----------------

using System;

using System.Data;

using System.Collections;

 

namespace Demo_DataTableRemoveDupRows

{

class Class1

{

[STAThread]

static void Main(string[] args)

{

 

// create an example datatable with duplicate rows

DataTable tbl = new DataTable();

 

tbl.Columns.Add("ColumnA");

tbl.Columns.Add("ColumnB");

tbl.Columns.Add("ColumnC");

for(int i = 0; i<10; i++)

{

DataRow nr = tbl.NewRow();

nr["ColumnA"] = "A" + i.ToString();

nr["ColumnB"] = "B" + i.ToString();

nr["ColumnC"] = "C" + i.ToString();

tbl.Rows.Add(nr);

// duplicate

nr = tbl.NewRow();

nr["ColumnA"] = "A" + i.ToString();

nr["ColumnB"] = "B" + i.ToString();

nr["ColumnC"] = "C" + i.ToString();

tbl.Rows.Add(nr);

}

 

PrintRows(tbl); // show table with duplicates

 

//Create an array of DataColumns to compare

//If these columns all match we consider the

                  //rows duplicate.

DataColumn[] keyColumns =

                              new DataColumn[]{tbl.Columns["ColumnA"],

                                               tbl.Columns["ColumnA"]};

 

//remove the duplicates

RemoveDuplicates(tbl, keyColumns);

 

 

PrintRows(tbl); // show table again

Console.ReadLine(); // pause to view output

 

}

/// <summary>

/// Removes duplicate rows from given DataTable

/// </summary>

/// <param name="tbl">Table to scan for duplicate rows</param>

/// <param name="KeyColumns">An array of DataColumns

///   containing the columns to match for duplicates</param>

private static void RemoveDuplicates(DataTable tbl,

DataColumn[] keyColumns)

{

int rowNdx = 0;

while(rowNdx < tbl.Rows.Count-1)

{

DataRow[] dups = FindDups(tbl, rowNdx, keyColumns);

if(dups.Length>0)

{

foreach(DataRow dup in dups)

{

tbl.Rows.Remove(dup);

}

}

else

{

rowNdx++;

}

}

}

 

private static DataRow[] FindDups(DataTable tbl,

int sourceNdx,

DataColumn[] keyColumns)

{

ArrayList retVal = new ArrayList();

 

DataRow sourceRow = tbl.Rows[sourceNdx];

for(int i=sourceNdx + 1; i<tbl.Rows.Count; i++)

{

DataRow targetRow = tbl.Rows[i];

if(IsDup(sourceRow, targetRow, keyColumns))

{

retVal.Add(targetRow);

}

}

return (DataRow[]) retVal.ToArray(typeof(DataRow));

}

 

private static bool IsDup(DataRow sourceRow,

DataRow targetRow,

DataColumn[] keyColumns)

{

bool retVal = true;

foreach(DataColumn column in keyColumns)

{

retVal = retVal && sourceRow[column].Equals(targetRow[column]);

if(!retVal) break;

}

return retVal;

}

 

private static void PrintRows(DataTable tbl)

{

for(int i=0; i<tbl.Rows.Count; i++)

{

Console.WriteLine("row: {0}, ColumnA: {1}, ColumnB: {2}", i, tbl.Rows[i]["ColumnA"], tbl.Rows[i]["ColumnB"]);

}

 

}

}

}

--------- End Demo Code ----------------

copy Outlook Calendar items from one folder to another

For Outlook 2010


Clearing the filter from an existing view


To clear the filter from an existing tabular view, follow these steps:

  1. Click to select the Outlook Calendar folder.

  2. On the View tab, click Change view, and then click to select one of the tabular views such as By List or ByCategory.

  3. On the View menu, click Reset View.

  4. Click Yes to reset the view to the original settings.


Defining a new tabular view


To define a new permanent tabular view, follow these steps:

  1. Click to select the Calendar folder.

  2. On the View tab, click Change view, click Manage Views, and then click New.

  3. Type a name for the new view, click to select Table, and then click OK.

  4. In Advanced View Settings, click Sort.

  5. In the Sort items by list, click to select Start and Ascending.

  6. In the Then By list, click to select (none), and then click OK.

  7. Click OK, and then click Apply View.


Either of the previous procedures will display a list of all Calendar items.

After all items are displayed, follow these steps:

  1. To select all items, use the keyboard shortcut, CONTROL+A.

  2. To copy the items, use the keyboard shortcut, CONTROL+C.

  3. Click to select the destination folder.
    Note To paste the items correctly, the destination folder must be a calendar folder.

  4. To paste the items, use the keyboard shortcut, CONTROL+V.


This process inserts a copy of all the Calendar items into the destination folder.

Additional option for Outlook 2010



  1. On the Folder tab, click Copy Calendar.

  2. Select the folder location where you want the calendar to be saved, and then click OK.


NoteTo copy the items correctly, the destination folder must be a calendar folder.

For Outlook 2007, 2003, 2002, 2000


Clearing the filter from an existing view


To clear the filter from an existing tabular view, follow these steps:

  1. Click to select the Outlook Calendar folder.

  2. On the View menu, point to Current View, and then click to select one of the tabular views such as Events or By Category.

  3. On the View menu, point to Current View, and then click Customize Current View.

  4. In the View Summary dialog box, click Filter, click Clear All, and then click OK twice.


Defining a new tabular view


To define a new permanent, tabular view, follow these steps:

  1. Click to select the Calendar folder.

  2. On the View menu, point to Current View, click Define Views, and then click New.

  3. Type a name for the new view, click to select Table, and then click OK.

  4. In View Summary, click Sort.

  5. In the Sort items by list, click to select Start and Ascending.

  6. In the Then By list, click to select (none), and then click OK.

  7. Click OK, and then click Apply View.


Either one of the previous procedures will display a list of all Calendar items.

After all items are displayed, follow these steps:

  1. On the Edit menu, click Select All.

  2. On the Edit menu, click Copy.

  3. Click to select the destination folder.

  4. On the Edit menu, click Paste.


This process inserts a copy of all the Calendar items into the destination folder.

check if node exists









using System;
using System.IO;
using System.Xml;

public class Sample
{
public static void Main()
{
XmlDocument doc = new XmlDocument();
doc.Load("booksort.xml");

//Select the book node with the matching attribute value.
XmlNode nodeToFind;
XmlElement root = doc.DocumentElement;

// Selects all the title elements that have an attribute named lang
nodeToFind = root.SelectSingleNode("//title[@lang]");

if( nodeToFind != null )
{
// It was found, manipulate it.
}
else
{
// It was not found.
}
}
}

Monday 11 June 2012

Import Excel Sheet to SharePoint List



In this article, we will learn how to export the excel data to the SharePoint list.
Steps:

1. Click on Site Actions -> More Options


2. Now click on the Lists -> Select Import Spread Sheet from the type -> then Click Create


3. Give the Name and Description of the List to be created and then browse the Excel Sheet to be uploaded


4. Clicking on Import option, you will find see a popup window opens. Select Range of Cells in the Range Type


5. This option allows you to select the table columns and rows in excel as shown below. After selecting, you will see the selected field’s column and row data being populated in the Select Range field in the popup window


6. Now click on Import in the popup window. Your SharePoint list will be created from the Excel Sheet and the values are also populated as shown below:


You may face some issues while importing the Excel Sheet to SharePoint and the solution is follows:

Error: “Method ‘Post’ of object ‘IOWSPostData’ failed” in SharePoint


Solution:

 Ã˜  Open the Excel Sheet Add-In EXPTOOWS.XLA which will is available at the following location C:\Program Files\Microsoft Office\Office12\1033 by default.

 Ã˜  Press Alt+F11 to display the Visual Basic code editor. Locate the form named "PublishForm" under the folder "Forms" and open the code view of this form.

 Ã˜  Search (Ctrl+F) for the line "lVer = Application.SharePointVersion(URL)" and place a new line "lVer=2" after that line.

 Ã˜  Now try to import the Excel Sheet to the SharePoint, you will not get any errors.


Error: "The specified file is not a valid spreadsheet or contains no data to import"




Solution:

This error occurs when the site you are opening do not have permission to file system. To give permission follow the below steps:

In Internet Explorer click Tools --> Internet Options -> Click Security tab --> Select Trusted Sites --> In the Sites add your URL here.

Now you will be able to import the file properly.

Hope this post helps you! Please free to comment and share this post.

Friday 8 June 2012

How to Find the Duplicate Values in ArrayList

contacts.Sort();

for (int i=1; i <= contacts.Count-1; i++)
{
Console.WriteLine(contacts[ i ]);
Console.WriteLine(contacts[ i-1] );
if(contacts[ i ].ToString() == contacts[ i-1 ].ToString())
{
Console.WriteLine("Duplicate: "+contacts[ i ]);
}
}

Finding Duplicates with SQL

Here's a handy query for finding duplicates in a table. Suppose you want to find all email addresses in a table that exist more than once:
SELECT email, 
COUNT(email) AS NumOccurrences
FROM users
GROUP BY email
HAVING ( COUNT(email) > 1 )

You could also use this technique to find rows that occur exactly once:
SELECT email
FROM users
GROUP BY email
HAVING ( COUNT(email) = 1 )

The difference between Public, Private, Protected, and Nothing?


Access modifiers


public
The type or member can be accessed by any other code in the same assembly or another assembly that references it.

private
The type or member can only be accessed by code in the same class or struct.

protected
The type or member can only be accessed by code in the same class or struct, or in a derived class.

internal
The type or member can be accessed by any code in the same assembly, but not from another assembly.

protected internal
The type or member can be accessed by any code in the same assembly, or by any derived class in another assembly.


Static
The static modifier on a class means that the class cannot be instantiated, and that all of its members are static. A static member has one version regardless of how many instances of its enclosing type are created.

A static class is basically the same as a non-static class, but there is one difference: a static class cannot be instantiated. In other words, you cannot use the new keyword to create a variable of the class type. Because there is no instance variable, you access the members of a static class by using the class name itself.

Static classes are often used as services, you can use them like so:
MyStaticClass.ServiceMethod(...);